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(17.2b)Calculate the pH of 620. mL of a 0.306-M solution of nitrous acid before and after...

(17.2b)Calculate the pH of 620. mL of a 0.306-M solution of nitrous acid before and after the addition of 0.179 mol of sodium nitrite.

pH befor addition =
pH after addition =

0 0
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Answer #1

Vol cd Sol SRO ML = O620L MHNO 0306 M ho t hole Nat 0.179 CNaNa2J = 0 9 ORG8 M 3.620 CHNO) = pk a 3.396 ureate tH3 0t 3 add C

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