Homework Answers
A)
let car B catch car A after time "tcatch"
VB = speed of car B
VA = speed of car A
XAi = initial position of car A = DA
XA = position of car A after time "tcatch" = ?
Position of car A after time "tcatch" is given as
XA = XAi + VA tcatch
XA = DA + VA tcatch eq-1
XBi = initial Position of car B = 0
XB = Position of car B after time "tcatch" = ?
Position of car B after time "tcatch" is given as
XB = XBi + VB tcatch
XB = 0+ VB tcatch eq-2
for the car A to catch car B ,
XA = XB
DA + VA tcatch = VB tcatch
VB tcatch - VA tcatch = DA
tcatch = DA / (VB - VA )
b)
position of car B is given as
XB = 0+ VB tcatch
XB = VB (DA / (VB - VA ))
XB = VB DA / (VB - VA )
dpass = VB DA / (VB - VA )
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