Question

Aqueous sulfuric acid H2SO4 reacts with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. If 70.8g of sodium sulfate is produced from the reaction of 87.29g of sulfuric acid and 111.1g of sodium hydroxide, calculate the percent yield of sodium sulfate. Be sure your answer has the correct number of significant digits in it.

Answer 1

H₂ SO 4 + 2NaOH - Nasou + 2H₂O Molar mas) 98.079 39.99 (g/mol) 142.04 Stiochemetod mass Requised 1x 98.079 (9) 2x39,99 (gl 1x142.04 (21 2x18 (91 198.079 (21) 9.98 (21] [142.046) 36(21) Given 87.29 (9) H₂ sou & 111.1 (g) NaOH -> Give 70.86) Alco. to Reaction Nazsoy) 98.079 (9) H₂ jou = 79.980) Noon Actual yield than 87.29 (9) H2 30 = 79.98 x 87.29 (g) Naon 98.079 = 71-1819 (9) Naon

But we have 1 1 1. 1 (9) Naon so Neol in excess and H₂ sou is limitin reactan Alco to Reaction 98.079 (G) Hz sou = 142.04, (g) Nuz sou than 87.29 (2) H₂SO4 = 142.04 x 87129 (g) Nagsoy. 98.079 = 126.4151 (2) Narso theoretical yield % Yield = vi Actual yield theoretical yield 0.8 xloo = 56.00 % 126.4151