Question

[Review Topics] [References) Compounds X and Y are both CH, Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C H 4 alkene. Both X and Y undergo an Sy2 reaction with sodium iodide in acetone solution to give CH I products; in this reaction Y reacts faster than X What is the structure of X? . Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right comer • Separate structures with + signs from the drop-down menu.

Answer 1

Answer ucz ho 2, 3-dimethyl Pentane In E2 eliminaticom both X and Y give single alkene. It indicate both X & Y have only one 13-H atom. CyH14 a Y Reacts with sodium iodide in acetone faster than X Wirin SNe reach om indicate Y is substrate and x react slowly. means it is 2° substrate. structure Y Stractere X era 2) X= Cyhiscl and Y= 6H15 Br as X undergoes the E2 elimination to gives single alkene product Z. This indicate x has only one type o B-hydrogen atom. Also X react readily in sne mechanism with Na I in acetone. The Poodluct zon hydrogenation gives B ethyl Pentene. Y also undergo € 2 eliminahon to gives single alkene that is isomeric with z but Y does not react cořth Nail acelene under similar 5N2 reach on indicate , it is gº substoate. 3° alkyl bromide. امیہ ر و کر ر NI Nas aceleme Zoro No Reach.com No mentione d for being acelone

Answer 2

For #2