8.
Acetone have two peaks : strong peak at 189 nm corresponds to -->* (higher energy required and it is allowed transition so strong) and weak peak at 280 nm corresponds to n-->* (lesser energy required and it is non-allowed transition so less intense )
(what is wrong with answer !)
2. Cyclohexane : boat and chair
At 298 K ; E(c) = 0 and E(b) = 22000 J/mol
(a) Molecular partition function : ( 2 energy states ) (e0 = 1)
q = 1 + exp(-E(b)/RT
q = 1 + exp(-22 x 103 J/mol /(8.314 J/k-mol x 298 K))
q = 1.0001
It suggests that only one energy level will be occupied at this temperature.
(b) Nc / N and Nb/N (boltzmann most probable distribution )
Nc / N = exp(-E(b)/RT) = exp(0) = 1
Nb / N = exp(-E(b)/RT) = exp(-22 x 103 J/mol /(8.314 J/k-mol x 298 K)) = 1.4 * 10-4
(c) comparing two conformations :
The relative population of the two conformations at a given temperature (298K) can be found from t
Nb /Nc = exp(-22 x 103 J/mol /(8.314 J/k-mol x 298 K)) = 1.4 * 10-4
or Nc/Nb = exp(22 x 103 J/mol /(8.314 J/k-mol x 298 K)) = 7143
This shows the very low population of the boat conformation at 298 K .
So, chair conformation is more populated.
Dang. That's all I was given. Thank you for your help! (8) The C = Ö...
(6) The rate of fluorescence process is the rate of UV absorption process. The rate of fluorescence process is A the rate of phosphorescence process. ster than (b) slower than (c) about the same as (8) The C = Ö group in acetone (CH3CO CH3) has a strong absorption line at 189 nm, and a weak absorption line at 280 nm. The line at 280 nm corresponds to a transition; and the line at 189 nm corresponds to a_ B....
(2) Cyclohexane (CH) has two conformations, i.e. the chair conformation (e) and boat conformation (b). At 298 °K, the chair conformation (e) is at the ground state with energy = 0; and the boat conformation (b) is at the energy level of 22,000 J/ mol. (i) Calculate the molecular partition function (q) of cyclohexane at 298 ®K. (ii) Calculate the Boltzmann distribution (the most probable distribution) of the two conformations, and respectively. (iii) Compare these two conformations, which conformation is...
Okay! Thank you! B) The C = Ö group in acetone (CH3CO CH3) has a strong absorption line at 189 nm, and a weak absorption line at 280 nm. The line at 280 nm corresponds to a @ transition; and the line at 189 nm corresponds to a_ B.! transition. (a) a → (c) r n lộn **
Can you help me answer questions 3)a)i)ii)iii)iv).thank you so much for your help.These questions are based on thermodynamics.I really appreciate your kindness and help Here are the updated questions.I provide you with bigger and clearer pic for all the subparts.I hope you can help me.thanks a lot. CH (9) H20 (9) 186 1189 0,09 205 ThermodyWUM 301) Use the data in the foblo 600W- 1 0 Hon Compound AS CT mol KP write the b0/0 for the combustion of methane...