Question

1. Use VSEPR theory to predict the molecular geometry for each of the following molecules, indicate whether each bond in it is a bord, and provide the hybridization scheme for each non-hydrogen atom. a. H_C = CHCH = CH2 b. (HOCH2)2C(CH2)COOH C. CH COOCH(CH)CH = CHC = CCH d. CH,OHCH(NH,)COOH e. (CH3)2CHCH3CH(NH2)COOH

please dont forget to explain also in iupac i just need b ans e and for first quesition i dont know how to write moleculer geometry plase explain

Answer 1

@ CECH-CHECHO -> Here all o carbons are sp hybridised, so. This molecule have plana gemely Hybridistic, = Bonding pairslo) + Lone pairs por ist carbon = 3 = sp - planer 2 ca, ben 3 = Sp - planas 3rd carbon = ] =sp i plana yth carbon = 3= sp planar. C-CLOH | | | | t 1 - cooh -> sp? - planar 2-4 - Sp? Tetraheday 3,47 spa y Tetrahedral s, sp - Tetrahedra. CH, hoa củ - 1 - 2 - 3 C19 17 Sal y Tetrahedral San 2 sp planar. 8, 9-58 Tetrahedrla 3 - Spl-Tetrahedret 4- spy planar s spa planar SK linear cs Scan 6 - linear Cam Sana SY

NH2 -CH-COOH ay spy Tetrahedril. buispl_getrahedra ca sprao planar. city NHL ayspy Tetrahedrl by spy Td exsp Td dyspyrd, f spetd, et spy placiara - po 1-(2-(bromo ethul) Cyclopropyl)-y-(tert-butyl cyclohenaue. Hoy, NHL INOL 4-amino-5-nitro-2-propyl pentan-1-ol cs Store prian't, OH NH₂7 NO2 CamScanner