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A voltaic cell utilizes the following reaction and operates at 298 K. 3 Ce+ (aq) + Cr(s) + 3 Ce3+ (aq) + Cr3+ (aq) (a) What i
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- Reduction 3 ce 4+ + Be ++3+. Oxidation E = E Cathodo - Enode = 1.61V-(-0.74) a) E = 2.35 V (std condition 16) E= EO -0.059

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