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2. A 0.500-gram sample of a weak, nonvolatile monoprotic acid, HA, was dissolved in sufficient water to make 50.0 milliliters
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Answer #1

A. After rinsing with distilled water , there will be certain amount of water in the burette. Hence , it will decrease the strength of the basic solution in the burette. We calculate the strength by using the formula V1S1 = V2S2 where , V1 = volume of weak acid taken in the conical , S1 = strength of the weak acid , V2= volume of the base added , S2 = strength of the base added in the system.

So , when the strength of the base is decreased, more amount of the basic solution will have to be added . So , in calculation , when the volume is written more than the usual , the calculated strength of the base will be lower than usual. Hence , alternatively the calculated molar mass of the weak acid will be high.

B. Adding extra water means diluting the solution . So , diluting the solution will decrease the volume of base to be added . Hence , molar mass of the acid will be lower than usual.

C. Normally the equivalence pH of the titration of weak acid and strong base will be around 8. Hence , using an indicator of pH 5 will show colour change at around pH 5 , which is actually lower value than equivalence point. Hence , the calculated volume of base will be low which eventually get lower the molar mass value of the weak acid.

D. When a bubble is passed in the burette , it will show a higher value than added amount of base. Hence , the added value of base will be higher than usual ,which will increase the molar mass will be higher than ususal.

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