16/ For PbCl2 (K.p = 2.4 x 10), will a precipitate of PbCl2 form when 0.10...

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Answer #1

Q -16 ) A precipitate form when Q > K_sp

[ Pb²⁺ ] = ( 3 x 10^-2 M) x ( 0.1 litre ) / ( 0.5 litre ) = 6 x 10^–3 M

[ Cl^— ] = ( 9 x 10^-2 M ) x ( 0.4 litre ) / ( 0.5 litre ) = 7.2 x 10^–2 M

Q = [ Pb²⁺ ] [ Cl^—]² = ( 6 x 10^-3 ) x ( 7.2 x 10^-2 )² = 3.11 x 10^–5
since Q < K_sp no precipitate will form correct answer is c option

Q - 17 ) P^ka = — log ( 3.2 x 10^–8 ) = 7.5

P^H range of buffer is from( P^ka —1 to P^ka + 1) that is from 6.5 to 8.5

answer is c option

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Answer 2

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