Question

Use the References to access important values if needed for this question. The normal boiling point of liquid diethyl ether is 308 K. Assuming that its molar heat of vaporization is constant at 27.8 kJ/mol, the boiling point of C,H,OC Hz when the external pressure is 1.38 atm is K.

Answer 1

At normal boiling point of any compound vapor pressure of compound is equal to catmosphere pressure ie. I atm » vapor pressure of diethyl ether at 308k Pi = latm noomal boiling point of diethyl ether & Ti = 308k molar heat of vaponzation & AHNO Huap 27.8 kJ Imol R = ideal gas constant 0.008314 KJ K 1 moly external vapour Pressure P2 = 1138 atm To = ? Clausius clapeyrun equation - ΔΕΝ in otherbot

In 138 atom 1 - - 27.8 kJ molt x 11-1 1-0 atm / 0.008314 KI KI molt To = 376 Hence, the boiling point of Cats Ucatis , when the external pressure is 1.38 atm is 30k Pleaue Rate