Need help on 11 (part 1) and 12 (part 2). please and thank you.
(011) Part (1 of 2) : What is the speed of each seat?
012 (Part 2 of 2) : If a child of mass 37.1 kg sits in a seat, what is the tension in the chain?
using eq.2 & we get
FT = m g / sin '
FT = [(37.1 kg) (9.8 m/s2)] / sin 67.10
FT = [(363.58 N) / (0.9211)]
FT = 394.7 N
Need help on 11 (part 1) and 12 (part 2). please and thank you. ion 18-19...
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