Kw = 6.70×10-14 at 500c.
pKw = - log (6.70×10-14) = 13.17
Now, Kw = [H+] [OH-]
Or, - log ([H+] [OH-]) = - log (Kw)
Or, - log[H+] - log[OH-] = pKw
Or, pH + pOH = pKw
Or, pH + 3.80 = 13.17
Or, pH = (13.17 - 3.80)
Or, pH = 9.37
A solution has a pOH of 3.80 at 50°C. What is the pH of the solution...
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