Homework Answers
HCl dissociates as:
HCl(aq) + H2O(l) —> H3O+(aq) + Cl-(aq)
use dilution formula
M1*V1 = M2*V2
1---> is for stock solution
2---> is for diluted solution
Given:
M1 = 0.5 M
V1 = 3 mL
V2 = 100 mL
use:
M1*V1 = M2*V2
M2 = (M1*V1)/V2
M2 = (0.5*3)/100
M2 = 0.015 M
[H3O+] = 0.015 M
use:
pH = -log [H3O+]
= -log (1.5*10^-2)
= 1.8239
Answer: 1.82
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Concentrated hydrochloric acid is 38% HCl by weight and has a density of 1.19 g/mL. A solution is prepared by measuring 67 mL of the concentrated HCl, adding it to water, and diluting to 0.800 L. Calculate the approximate molarity of this solution from the volume, percent composition, and density.
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