Solution
Q1 Part (a)
Let S1 = {H, TH, TTH, TTTH, ……….. }, and
S2 = {TTTT, HTTTT, THTTTT, HTHTTTT, THHTTTT, …….}. Then,
S = S1∪ S2. Answer 1
Q1Part (b)
Sample space, S = {x, y | 1 ≤ x ≤ 5, 1 ≤ y ≤ 5, x,y ∈ N} Answer 2
Q2 Part (a)
M ∪ N = {x | 2 < x < 12} Answer 3
Q2 Part (b)
M ∩ N = {x | x = 5} Answer 4
Q2 Part (c)
(S ∩ N)’ = {x | 4 < x < 12}’
= {x | x ≤ 4, x ≥ 12} Answer 5
Q2 Part (d)
M’ ∩ N’ = {x | x ≤ 2, x ≥ 12} Answer 6
Q3 Part (a)
Sum = 4 => (1, 3), (2, 2), (3, 1) are the only possibilities. Since totally there (6 x 6) = 36 possibilities, the required probability = 3/36 = 1/12 Answer 7
Q3 Part (b)
Sum = at most 4 => Sum = 2 ,3 or 4 => (1, 1), (1, 2), (2, 1), (1, 3), (2, 2), (3, 1) are the only possibilities. Since totally there (6 x 6) = 36 possibilities, the required probability = 6/36
= 1/6 Answer 8
DONE
all questions please 1. (a) What is the sample space S for flipping a coin until...
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