Balanced equation: 2H2(aq)+ O2-----> 2H2O(l)
Thereotical Yield:
4 g O2x(1 mol O2/32 gO2)X 2 mol H2O/1 mol O2)x18 g H2O/1mol H2O= 4.5 g H2O
0.55 g H2(1 mol H2/2 g H2)(2 mol H2O/2 mol H2O)(18 gH2O/1 mol H2O)= 4.95 g
Since O2 produce less amount of H2O , it is completely consumed hence it is limiting reagent and H2 is excess reagent.
Puzzle 2 (2 t) I mix 4.00 Rofes and $50 of hydrogen in the grams of...