Often we have distributions of charge for which integrating to find the electric field may not...

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Often we have distributions of charge for which integrating to find the electric field may not be possible in practice. In such cases, we may be able to get a good approximate solution by dividing the distribution into small but finite particles and taking the vector sum of the contributions of each. To see how this might work, consider a very thin rod of length -12 cm with uniform linear charge density λ=32.0 nC/m. Estimate the magnitude of the electric field at a point P a distance d - 6.o cm from the end of the rod by dividing it into n segments of equal length as illustrated in the figure below for 4. Treat each segment as a particle whose distance from point P is measured from its center. Find estimates of Ep for n= 1,2,4, and 8 segments n -1, Ep-2400 n - 2, Ep N/C N/C N/C N/C Need Help? Read

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Answer 1

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Sol Given o 12 m 9 3.34x10 (o. 0225) ( IIo -29 01.33 トt/c

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