first write the both the reactions and then rewrite them to obtain the final equation and the k value as follows
please explain well. I don't understand at all. Explain all steps ans math involved. 1. Ammonia...
please explain well. I don't understand at all. Explain all
steps ans math involved.
3. Elemental sulfur is a molecular solid. The most stable allotrope of elemental sulfur is actually the eight-membered ring, Ss. Thus, the elemental sulfur in the H2S formation reaction shown in question 1 should actually be written as Sa(s). Use the equilibrium constant given in question 1 to find K for the following reaction: 8H2(g) + S«(s) - 8H2S(8) K ? 1. Ammonia and hydrogen sulfide...
Help please! Show work
Problem Set 13 CHEM 1252 October 21, 2019 Textbook Reading Assignment: 14.6-10 uce Problems: 14.63,66-68,70,73,75,77,79,83,86-87,89,101,107,111-115,119 1. Ammonia and hydrogen sulfide can both be formed directly from their elements. At 90 °C... N2(g) + 3H2(g) + 2NH3(g) K = 120 H2(g) + S(s) = H2S(8) K = 0.068 Find K at 90 °C for the following reaction: 2NH3(g) + 3S() = 3H2S(8) + N2(g) K = ? entrations ctants and ture at ing values and -14 ee-energy...
With this problem I understand
the ICE table used to solve the problem as well as setting up the
Kc. I just don't understand how the small-x approximation applies
to this problem since it doesn't seem to follow the rules for x is
small approximation. I tried comparing the value of 0.097
M/9.30*10^-8 which was 1.0*10^6 which is smaller than 400 so the x
is small doesn't apply, however I can't seem to find another method
that helps me simplify...
1)
2)
3)
Please explain step by step so I can understand how answer was
obtained
Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate = k [X] [Y]2[z] The rate of reaction will increase by a factor of 06 OOOO At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICI(g) = 12(g) + Cl2(g). What is the equilibrium concentration of Cl2 if 4.27...
1. Write down the equilibrium constant expressions, Ke and K, for each of the following reactions: (a) H(g)Cl(g) 2 HCl(g) (b) 2 C(s)+O2(g) 2 CO(g Ag (aq)Cl(aq) (c) AgCl(s) (d) 2 O(g) 3 0:(g) 2. A 1.0 L evacuated flask was charged with 0.020 mol of N,O, and 0.060 mol of NO2 at 25.0 C. After equilibrium was reached the NO2 concentration was found to be 0.0140 M. What is the equilibrium constant Ke for the reaction? N2O4(g) 2 NO:(g)...
show all the steps please.
I. What is the heat capacity of 185g of liquid water? How many Kilojoules are needed to raise the temperature of 10 kg of liquid water from 24.6°C to 46.2°C and 38.5 mol of water from 38.1°C to 79.4°C? Ans: 774.04J/gC, 903.74Kj, 119.75KJ 2. A 2.200 g sample of quinone, C&402. is burned in a bomb Calorimeter whose total heat capacity is 7.854 kJ C. The temperature of calorimeter increases from 23.44°C to 30.57C. What...
please show all work, no cursive.
math work should be in dimensional analysis and use starting
amount and make sure each number has its units so that I can
understand how to do this.
5) Aluminum reacts with hydrochloric acid to produce hydrogen gas according to the equation below. 2 Al(s) + 6 HCl (aq) + 2 H2 (g) + 3 AlCl3 (aq) a. Balance the equation. (2 pts) b. What volume of hydrogen gas (in mL) is produced when...
please solve all
FREE ENERGY AND CALCULATING AG FOR REACTIONS (Math) 21. Any reaction will be spontaneous if AG > 0 d. AS < 0 b. AG0 AH, <0 AS > 0 a. e. c. From AGformations 22. What is the AG for the reaction given: CH_(8) +20,(8) CO2(g) + 2H2O(g) Substance CH.(g) CO.(g) H.O(g) AGform (kJ/mol) 50.8 394.4 -228.57 a. -50.8 kJ/mol b. -- 751 kJ/mol c. -113 kJ/mol d. -115 kJ/mol e. -807 kJ/mol 23. Determine AG for...
It's a lot, but I really don't
understand these questions. Please explain! Thank you!
QUESTION 2 What volume (in L) is occupied by 1.29 moles of gas at -24.5 °C with a pressure of 704 mm Hg? QUESTION 3 A piston with a volume of 800.8 mL is filled with a gas at 304.1 K and 717.4 mm Hg. The piston is then compressed by 192.4 mL and cooled to 243 K. What is the pressure in atm) of the...
please explain I don't understand how to do this
<Chapter 19 Exercise 19.50 with feedback 10 of 12 PartA 2Ca(s) + 02(g) - 2Ca0(s) ??,xn--1 269.8 kJASrx,--364.6 J/K Calculate the free energy change for the reaction at 26 C Express your answer using four significant figures You may want to reference Pages 784 -788) section 17.6 while completing this problem. AG kJ Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining