Homework Answers
1.
Target concentration = 0.151 M = 0.151 mol/L
Hence, 0.151 mol of potassium phosphate is needed per litre to make a 0.151 M solution.
We need to make 500 mL=0.500 L solution in a volumetric flask.
Hence, number of moles of potassium phosphate needed is
Molar mass of potassium phosphate 
= 212.27 g/mol
Hence, amount of potassium in gram needed to make the required solution is
Answer rounded to 3 significant figures.
Hence, we should add approximately 16.0 grams of solid potassium phosphate.
2.
We have 0.177 M chromium (II) bromide 
.
Hence, there are 0.177 mol of CrBr2 in a litre of the solution.
We need 9.03 gram of the salt.
Molar mass of CrBr2 = 211.804 g/mol
Hence, number of moles of CrBr2 needed is
Hence, the volume of solution that contains 0.0426 mol can be calculated as
Note: Answer rounded to 3 significant figures.
Hence, the volume of solution that has 9.03 g of salt is 241 mL.
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