Answer
(A) we know that the sum of relative frequency must be equal to 1
So, we can write it as
f(A) + f(B) + f(C) + f(D) = 1
using the data table above, putting the values of frequencies, we get
0.22+0.26+0.09 + f(D) = 1
0.53+f(D) = 1
subtracting 0.53 on each side, we get
f(D) = 1 - 0.57 = 0.43
So, relative frequency of D is 0.43
(b) total sample size = 900
relative frequency of D is 0.43
So, Frequency of class D = relative frequency*sample size = 0.43*900 = 387
(c)
Class | Frequency |
A | relative frequency*sample size= 0.22*900=198 |
B | relative frequency*sample size= 0.26*900=234 |
C | relative frequency*sample size= 0.09*900=81 |
D | relative frequency*sample size= 0.43*900=387 |
(D) Percent frequency = relative frequency*100
Class | Percent Frequency |
A | 0.22*100 = 22% |
B | 0.26*100 = 26% |
C | 0.09*100 = 9% |
D | 0.43*100 = 43% |
A partial relative frequency distribution is given. a. What is the relative frequency of class D...
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