12) acceleration =Net force / mass
a = qE/m
where q = charge , E = electric field
m = mass of the object
0.005 = 5*10^-6*E / 2*10^-6
E = 0.002 N/C
13) Electric field = kQ/r^2
so electric field at P can by doubled by doubling the charge Q
so option double the point charge 2Q is the correct answer
12. An object with a 5.0 HC charge is accelerating at 0.0050 m/s2 due to an...
An object of mass 3.0 mg and charge 2.0 μC is observed accelerating at a rate of 5.0 × 10-3 m/s2 under the sole influence of electric forces. The magnitude of the electric field experienced by the object is ... 1.3 × 102 N/C 1.5 × 10-1 N/C 1.5 × 10-2 N/C 7.5 × 10-3 N/C 3.0 × 10-14 N/C
15. Point P and point charge Q are separated by a distance R. The electric field at point Phas magnitude E. How could the magnitude of the electric field at point P be doubled to 25? O double the distance to 2R O reduce the distance to R2 reduce the distance to R/4 reduce the point charge to Q2 double the point charge to 20 11. What is the electric field strength atx-0 m, y-0 m produced by two electrons,...
A positively charged disk of radius R-0.0276 m and total charge 53.8 HC lies in the xz plane, centered on the y axis (see figure below). Also centered on the y axis is a charged ring with the same radius as the disk and a total charge of -35.1 HC. The ring is a distance d-0.0050 m above the disk. Determine the electric field at the point P on the y axis, where P is y 0.0100 m above the...
A particle P has an electric charge. Compared to a distance r from P, where the electric field has a strength of E, the magnitude of the electric field at a distance 2r from P is a) E/4 b) E/2 c) E d) 2E
An object carries a +15.5 HC charge. It is 0.525 m from a -7.25 uC charge. What is the magnitude of the electric force on the object? (u stands for micro. Remember, magnitudes are positive.) [?] N nte
A small object has a charge of q = 2e, where e is the charge on an electron. (a) Determine the electric potential (in V) due to the charge at a distance r = 0.100 cm from the charge.(b) Determine the electric potential difference in V) between a point that is 2r away and this point, that is V(2r) - V(r). (c) Determine the electric potential difference (in V) between a point that is r/2 away and this point, that is V(r/2)...
A +5.0 µC point charge is on the x-axis at x = -3.0 m, and a +2.2 µC point charge is on the x-axis at x = +1.0 m. Determine the net electric field (magnitude and direction) on the y-axis at y = +2.0 m. magnitude = N/C direction = ° counterclockwise from the +x-axis.
Problem 19.47 An object with a charge of 4.5 C and a mass of 1,5%10-2 kg experiences an upward etectric force, due to a uniform evectrie feld, equal in magnitude to its weight Part A Find the magnitude of the electric field Express your answer using two significant figures ANSWER N/C Part B Find the direction of the electric Seld ANSWER upward downward tothe left to the right O Part C If the eloctric charge on the object is doubled...
Basic Coulomb's law tells us that the electric field of a point
charge q, E=ke q/r2, scales with distance r
as 1/r2: when the distance increases by a factor of 2,
the magnitude of the field decreases by a factor of 4. We can write
this as E(r) ∝ 1/r2. An interesting and practically
important question is how the electric field of a group of charges
scales with distance (asymptotically) far away from the group. The
figure below depicts 3...
1-5 please
Questions 1.2 T The figure above shows two particles, each with a charge of +Q, that are located at the opposite corners of a square of side d. 1. What is the direction of the net electric field at point P? (D) 1 (E) 2. What is the potential energy of a particle of charge +2q that is held at point P? (A) Zero (B) 2 kgQcc) kq (D) 2kqQ (6) 2,2 kgQ d d d d q=3.0...