Question

Boron trifluoride gas is collected at -1.0 °C in an evacuated flask with a measured volume of 25.0 L. When all the gas has be
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Answer #1

Given:

P = 0.49 atm

V = 25.0 L

T = -1.0 oC

= (-1.0+273) K

= 272 K

find number of moles using:

P * V = n*R*T

0.49 atm * 25 L = n * 0.08206 atm.L/mol.K * 272 K

n = 0.5488 mol

Molar mass of BF3,

MM = 1*MM(B) + 3*MM(F)

= 1*10.81 + 3*19.0

= 67.81 g/mol

use:

mass of BF3,

m = number of mol * molar mass

= 0.5488 mol * 67.81 g/mol

= 37.22 g

Answer:

Mass = 37.2 g

Mol = 0.549 mol

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