Dana hits a volleyball so that it moves with an initial velocity of 6 m/s straight upward. If the volleyball starts from 2 m above the floor, how long will it be in the air before it strikes the floor?
initial velocity = V0 = 6 m/sec
height = h= 2 m
time = t = ?
h = - V0 * t + 1/2 * g * t^2
2 = - 6 t + 0.5 * 9.8 * t^2
2 = -6 t + 4.9 t^2
by solving the equation
time = t = 1.497 sec = 1.5 sec
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