Question

16.2 cell potential for the following cell was measured to 0.889 V at 25 ° C....

16.2 cell potential for the following cell was measured to 0.889 V at 25 ° C.

Pt (p) | H 2 (g, 0.95 bar) | H + (aq, 0.0010 M) || Fe3 + (aq, 0.0010 M), Fe2 + (aq, 0.010 M) | Pt (s)

a) Write the reaction formula for the cell.

b) Calculate the normal potential of the redox pair Fe3 + / Fe2 +.

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Answer #1

a Reaction in I LHE H₂ (9) HI e- RHE Fe 3+ + e - Feet Total Ron 1 Hit Fe 3+ H+ + Fe ²+ b) Nernst Eqn Ecell - Eest/Felt – 0.05

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