Question

Two positive charges each of charge q are fixed on the y-axis, one at y = d and the other at y = -d as in the figure shown below. A third positive charge 29 located on the x-axis at x = 2d is released from rest. a + 24 (a) Find a symbolic expression for the total electric potential due to the first two charges at the location of the charge 2g. (Use any variable or symbol stated above along with the following as necessary: Ke for the Coulomb constant.) V = (b) Find a symbolic expression for the electric potential energy of the charge 29. (Use any variable or symbol stated above along with the following as necessary: k, for the Coulomb constant.) PE = (c) Find a symbolic expression for the kinetic energy of the charge 29 after it has moved infinitely far from the other charges. (Use any variable or symbol stated above along with the following as necessary: ke for the Coulomb constant.) KE (d) Find a symbolic expression for the speed of the charge 29 after it has moved infinitely far from the other charges if its mass is m. (Use any variable or symbol stated above along with the following as necessary: ką for the Coulomb constant.)

Answer 1

charge 1 a fr 2d- abr 29 e e = √d ²7 (2 d)2 = daudz r = 5d charge 2 (a) to find total electric potentia V = Vitz » potential due to charge 2 potential due to Charge 2 Vakay + ka [V= 2kg shkuan - 5d (6) U=Potential energy = 2qV = 29x2 kq = 4 kq? 5d 5d

Expt. No... Page No. rential (c) to body starts from rest kenetic energy . At infinity Let Kinetic energy = kE Change in k E= AKE = KE-O trong best score barn Change on Work done by consewation Now Using work - Gregy conservation W work done by conservatue force = change in Kinetic energy We = -A U = Ui-U₂ (at infinity 6 KxZg potentiel емалу - 0 0 L potentiel energy at distance 2 d on x-axis Teacher's Signature :

- 4 kq2 - 0 √5 d W = ok. E =kiG. so (k. E = 4 kq2) 1 rsd D at infinity (d) At infinity Kit Akal KE - I mv2 so + mv2 - 4 kq? v² = 8 kq2 rsma Kas al infinity VC nd