Question

Checkpoint 2.07 (Multistep) A spring of stiffness 143 Nm, and with elaxed length 0.26 m, stands vertically on a table, as shown in the figure. Instead of compressing the spring with a heavy block, with your hand you push straight down on the spring until your hand is only 0.18 m above the table. (Assume that the positive y-axis points upward and is normal to the table.) Relaxcd length Push down ▼ Part 1 (a) what is now the vector L, with the spring compressed? By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Attempts: O of 9 used SAVE FOR LATER ▼ Part 2 (b) What is the magnitude of L? 리 the tolerarice is +/-296 By accessing this Question Ass stance, you will learn whlle you earn points based on the Point Potential Pollcy set by your Instructor Attempts: 0 of 9 used SAVE FO LATEN

Answer 1

part (1) since new location is at x = 0m, y = 0.18m, z = 0m therefore L^rightarrow = (0, 0.18, 0)m part (2) length Vertical-bar L^rightarrow Vertical-bar = 0.18 m part (3) unit vector L^cap = L^rightarrow/ Vertical-bar L^rightarrow Vertical-bar = (0i^cap + 0.18 j^cap + 0k^cap)/0.18 therefore L^cap = (0, 1, 0) part (4) stretch delta = L_f - L_i = (0.18 - 0.26)m delta = -0.08m part (5) force exerted on hand by the spring F^rightarrow = -K (delta_x i^cap + delta_y j^cap + delta_z k^cap) F^rightarrow = -143 [0i^cap - 0.08 j^cap + 0k^cap]N F^rightarrow = 11.44 N j^cap therefore F^rightarrow = (0, 11.44, 0) N