Answer:
when Solid cobalt(iii) oxide reacts with solid carbon it forms solid cobalt and carbon dioxide gas
The unbalance chemical equation will be
Co2O3(s) + C(s) --------> Co(s) + CO2(g)
The balance chemical equation is
2 Co2O3(s) + 3 C(s) --------> 4 Co(s) + 3 CO2(g)
Explanation:
We know Co(iii) means that cobalt has a 3+ positive charge meaning it has 3 less electrons that normal on it's outer shell, together with oxygen you get the formula Co2O3 which is a solid
Carbon is also a solid, C(s) solid Cobalt symbol is Co(s) and carbon dioxide is CO2(g)
So we have Co2O3(s) + C(s) --------> Co(s) + CO2(g)
This equation is not balanced though, we have two cobalt and three oxygen on one side with one cobalt and two oxygen on the other.
Co2O3(s) + C(s) --------> Co(s) + CO2(g)
First balance the oxygen to get 6 on both sides: so multiply Co2O3(s) by 2 and CO2(g) by 3
2 Co2O3(s) + C(s) --------> Co(s) + 3 CO2(g)
Now we have 3 carbons on the right, 1 on left and we have 4 Cobalt on the left but 1 on the right.So multiply C(s) by 3 and Co(s) by 4
Hence finally we get
2 Co2O3(s) + 3 C(s) --------> 4 Co(s) + 3 CO2(g)
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