Question

Correct The specific heat capacity of gold is 0.128 J/(g."C), therefore, the rock cannot be pure gold. Even if the substance (e.g., color) to confirm that it is pure gold (as opposed to lead). According to the C, value you ca Part C A55.0 g aluminum block initially at 27.5 ° C absorbs 725 J of heat What is the final temperature of the aluminum? Express your answer in degrees Celsius to one decimal place. VAO ? C T= Request Answer Submit Provide Feedback SAVE your work often and remember to LOG OUT of your account when finished. DO NOT turn off the computer. FO FB F7 F6 F5 F4 F3 &

Answer 1

We know that Q=mC∆T, where Q= heat absorbed, M= mass, C= specific heat and ∆T = change in temperature.

Here given that Q= 725J, m= 55g, C=0.900J/⁰C, g and initial temperature = 27.5 degrees

Q= mC(T2-T1)

725J = 55g * 0.900J/ ⁰C, g * (T2-27.5⁰C)

So T2= 42.1⁰C