Question

Concentration of HCI is 0.09655 M. Concentration of NaOH is 0.100 M. a) What is the pH at equivalence point? b) Moles of HCl at equivalence point? c) Moles of NaOH at equivalence point? d) Volume of NaOH at equivalence point? Volume NaOH added (mL) pH Moles of NaOH added 0.89 0.89 0.00010 0.89 0.00020 0.90 0.00030 0.91 0.00040 0.93 0.00050 0.94 0.00060 0.96 0.00070 0.98 0.00080 1.01 0.00090 1.03 0.00100 1.06 0.00110 LOS 0.00120 1.11 0.00130 1.15 0.00140 1.19 0.00150 1.24 0.00160 1.3 0.00170 1.37 0.00180 1.45 0.00190 1.55 0.00200 0.00210 1.99 0.00220 2.68 0.00230 10.86 0.00240 11.33 0.00250 11.54 0.00260 11.67 0.00270 11.73 0.00280 11.79 0.00290 11.85 0.00300 11.91 0.00310 11.95 0.00320 12.02 0.00330 12.1 0.00340 12.19 0.00350 12.2 0.00360 12.28 0.00370 12.34 0.00380 12.4 0.00390 12.25 0.00400 1.7

Answer 1

The problem was best over acid base titration.A equivalent the concentration of acid is equal to the concentration of base but in practice ideal condition not occur easily therefore there may be some acid or base equivalent point.

Solution of problem is given here.

@ pH at equiralence point (HA) = 4t = 0.09655 m Nooh = on = oo o.100m so Netot = 0.100 - oro 9655 = 0.00345 m According to table the pH mushould be of 0.00345 m oh should be: I PH= 12-14 - moles of Hel of equivalent point is zero. © moles of Nach of equivalent point is = 0.00345 M @ volume of wooh at equivalent point According to table given ir- 13 mL T 13.5 ml is more correct]. but not giren intable anned with CamScanner

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