Answer
(A)We know that the formula for margin of error is given as
ME =
in this case, z = 1.64 for 90% (using z distribution table), n = sample size = 35 and
setting the values, we get
ME =
So, required margin of error = 11.50(rounded to 2 decimals) or 11.5 (rounded to one decimal)
(B) We know that the formula for margin of error is given as
ME =
in this case, z = 1.96 for 95% (using z distribution table), n = sample size = 35 and
setting the values, we get
ME =
So, required margin of error = 13.75(rounded to 2 decimal) or 13.7(rounded to one decimal)
All other answers are arleady correct
cases of Thirty-five small communities in Connecticut (population near 10,000 each) gave an average of x...
Thirty small communities in Connecticut (population near 10,000 each) gave an average of 138.5 reported cases of larceny per year. Assume that is known to be 42.1 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities What is the margin of error? (Round your answers to one decimal place.) lower limit upper limit margin of error (b) Find a 95% confidence interval for the population mean annual...
Thirty-two small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 40.5 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit upper limit margin of error (b) Find a 95% confidence interval for the...
Thirty-two small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that o is known to be 42.1 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit 11.8 upper limit margin of error (b) Find a 95% confidence interval for...
Thirty-three small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 40.5 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit upper limit margin of error (b) Find a 95% confidence interval for the...
Thirty-one small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 43.5cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the upper, and lower limit? (Round your answers to one decimal place.) (b) Find a 95% confidence interval for the population mean annual number of reported larceny...
Thirty-one small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 43.5cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) (b) Find a 95% confidence interval for the population mean annual number of reported larceny cases...
Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 46 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that σ = 7.20 ml/kg for the distribution of blood plasma. We were unable...
14. Thirty small communities in Connecticut reported an average of 138.5 cases of larceny per year. If the population standard deviation is known to be 42.6 cases per year, find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities.
this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. ignment Scoring r last submission is used for your score. -/11 points BBUnderStat12 7.1.019. My Notes Ask Your Teac Thirty-three small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that is known to be 43.7 cases year. (a) Find a 90%...
Question1 10 pts Suppose 22 communities have an average of x 123.6 reported cases of larceny per year. Assume that is known to be 36.8 cases per year. Find a 90%, 95%, and 98% confidence interval for the population mean annual number of reported larceny cases in such communities. Compare the lengths of the confidence intervals. As the confidence levels increase, do the confidence intervals increase in length? The 90% confidence level has a confidence interval length of 1715; the...