Question

IV.3 (6 pts) The cauldron and solutions are initially at a temperature of 20.0°C. The heat capacity of the cauldron is C = 1.35 kJ.K1, the specific heat capacities and densities of the solutions are considered to be equal to that of pure water. The enthalpy of the reaction taking place is AH =-3.00 kJ.mol-1 (given for 1 mol of CO32-). What is the final temperature of the cauldron and its contents?

The answer is 20.2 degrees celsius, however, please explain how this answer is achieved using the unit factor of C= 4.184 J/K *g

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Thank you

Answer 1

2 Hel (aa) + NO₂ CO₂ (aq) → z nau (92) + H₂O (2) + 102 (9) No. of males of Hel = 1.00 mol x 2.006=2.00 moe 20.of moles of Na, 603 = 1.00 mol x 1.00l = 100 mol Hel AND NO₂ CO₂ REACT IN 2:1 mole RAMO HEAT RHEASED TO HE CAULORON = 3:00 kJ Hets Released - HEAT ABSORBTD By Solution CALDRON S + HEAT ABSORBED BY CAULD MASS of Solution - (1.00L + 2'001) * 1kg = 3000 kg = 3000.09 3.00 x 10°3 = 300.0gx 4.189. I x AT + 1.35 x10 of AT T 'gik AT= 0.2 K = 0.2°C AT - Tp - T : 012 • Tp = 0.2 'c + 20.0 - 20.2°c fimae Tempe RAURE -