Answer :- 64oC
explaination:-
Since
qlost.metal = qgained.zinc
we write
(mass) (∆t) (Cp.metal) = (mass) (∆t) (Cp.zinc)
Cp.metal = 0.45 where , metal = chromium
Cp.zinc = 0.387
(65) (120 - x) (0.45) = (95) (x-20) (0.387)
(65 X 0.45) / (95 X 0.39) = (x-20) / (120 -x)
(0.7894) X (120) + 20 = x. (1.7894)
x = 64.1o C
therefore final temperature of two piece of metal = 64o C
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O 81% E all VZW Wi-Fi 12:57 Exit 12 3. A 65.0 g piece of chromium...
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0'C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
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