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O 81% E all VZW Wi-Fi 12:57 Exit 12 3. A 65.0 g piece of chromium [cp 0.449 J/(g °C)] is heated to a temperature of 120.0°C a
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Answer #1

Answer :- 64oC

explaination:-

Since

qlost.metal = qgained.zinc

we write

(mass) (∆t) (Cp.metal) = (mass) (∆t) (Cp.zinc)

Cp.metal = 0.45 where , metal = chromium

Cp.zinc = 0.387

(65) (120 - x) (0.45) = (95) (x-20) (0.387)

(65 X 0.45) / (95 X 0.39) = (x-20) / (120 -x)

(0.7894) X (120) + 20 = x. (1.7894)

x = 64.1o C

therefore final temperature of two piece of metal = 64o C

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