Question

Hydrogen peroxide decomposes into water and oxygen according to the following reaction: 2H2O2(1)→ 2H2O(g) + O2(g) 0.11 g of H

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Answer #1

1)

Molar mass of H2O2,

MM = 2*MM(H) + 2*MM(O)

= 2*1.008 + 2*16.0

= 34.016 g/mol

mass of H2O2 = 0.11 g

mol of H2O2 = (mass)/(molar mass)

= 0.11/34.02

= 3.234*10^-3 mol

According to balanced equation

mol of O2 formed = (1/2)* moles of H2O2

= (1/2)*3.234*10^-3

= 1.617*10^-3 mol

Given:

V = 2.50 L

n = 1.617*10^-3 mol

T = 298 K

use:

P * V = n*R*T

P * 2.5 L = 0.0016 mol* 0.08206 atm.L/mol.K * 298 K

P = 0.016 atm

Answer: c

2)

Gas is changing to liquid.

So, heat must be released.

So, ΔHo is negative.

Reactant has more entropy than product because of presence of gas in reactant.

So, ΔSo is negative

Answer: d

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