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Suppose that the random variable X has a Weibull distribution with parameters a = 3.68 and...

Suppose that the random variable X has a Weibull distribution with parameters a = 3.68 and λ = 0.21.

Find the upper quartile of the distribution.

Round your answer to the nearest ten thousandth.

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Answer #1

here as we know for upper quartile probability p=0.75

x= (1/\lambda)(-ln(1-p))1/a = 5.2

( please revert for any clarification)

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