Question

An ice freezer behind a restaurant has a freon leak, releasing 37.70 g of C,H,F3CI into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weekss in a month

Answer 1

We have relation, 1 month = 4 weeks

$\therefore$ 6 month = 6 month $\times$ ( 4 weeks / 1 month ) = 24 weeks

37.70 g Freon is released in air in 1 Week .

$\therefore$ g of Freon released in air in 24 weeks = 24 weeks $\times$ ( 37.70 g / 1 week ) = 904.8 g

We have relation, 1 mol C₂H₂F₃Cl  $\equiv$ 3 mol F

Molar Mass of C₂H₂F₃Cl = ( 2 $\times$ 12.01 ) + ( 2 $\times$ 1.0079) + ( 3 $\times$ 19.00 ) + 35.45 = 118.48 g / mol

Molar Mass of F = 19.00 g / mol

$\therefore$ 118.48 g C₂H₂F₃Cl  $\equiv$ 3 $\times$ 19.00 g F

$\therefore$ 904.8 g C₂H₂F₃Cl  $\equiv$ 3 $\times$ 19.00 $\times$ 904.8 / 118.48 g F

904.8 g C₂H₂F₃Cl  $\equiv$ 435.29 g F

i e g of F released in air in 24 weeks = 435. 29 g

$\therefore$ kg of F released in air in 24 weeks = 435.29 g ( 1 kg / 1000 g ) = 0.4353 kg

ANSWER : kg of F released in air in 24 weeks = 0.4353 kg