Area under acceleration time graph is equals to speed.
So here we have to take area from t=0 to t=7 sec
So v= 2×(2-1)+3×(3-2)+2×(4-3) -2×(7-5)
Or v= 3m/s
Hence v at t= 7 sec is 3m/s
For next part see image
Answer all parts please. A car is initially at rest on a straight road. The qraph...
A car is initially at rest on a straight road. The graph shows the speed of the car as a function of time. 01 23 4 5 6 7 8 9 10 11 12 13 14 t (s) What is the speed of the car at t-6 s? 9.0 m/s You are correct Your receipt no. is 155-4446Previous Tries How much distance did the car cover in the first 9 seconds? Submit Answer Incorrect. Tries 1/12 Previous Tries Determine the...
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A car is initially at rest on a straight road. The graph shows the acceleration of the car along that road as a function of time. 0 -3 0 1 2 34 5 6 789 10 11 12 13 14 t (s) What is the speed of the car at t-7 s? Submit Answer Tries 0/12 What distance does the car cover in the first 8 seconds? Submit Answer Tries 0/12 What is the speed of the car at t-14...
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A car is initially at rest on a straight road. The graph shows the acceleration of the car along that road as a function of time. What is the speed of the car at t=6 s? What distance does the car cover in the first 8 seconds? What is the speed of the car at t=13 s? Determine the distance covered by the car between t=11 s and t=14 s? 4. 2 -1 -3 0 1 2 34 5 6...
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A car is initially at rest on a straight road. The graph shows the speed of the car as a function of time. What is the speed of the car at t=7 s? How much distance did the car cover in the first 8 seconds? Determine the distance covered by the car between t=8 s and t=13 s? What is the average speed of the car between t=4 s and t=7 s? 12 10 9 4 2 0 0 1...
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