Question

9.35 9.50 9.379.39 9.67 9.41 9.43 9.459.479.499.55 9.57 9.1 Identify the solute and the solvent in each solution composed of the following: a. 10.0 g of NaCl and 100.0 g of H, O b. 50.0 mL of ethanol, C, H, O, and 10.0 mL of H, O c. 0.20 L of O, and 0.80 L of N2 9.5 Water is a polar solvent and carbon tetrachloride (CCI) is a nonpolar solvent. In which solvent is each of the following, which is found or used in the body, more likely to be soluble? a. Caco, (calcium supplement), ionic water (why)? b. retinol (vitamin A), nonpolar celu c. sucrose (table sugar), polar H.O d. cholesterol (lipid), nonpolar E ccly Solubility nule For ione Compounds Polar-polar (scubie), non polar:non polar Soluble) Polar: non polar (NUT SUBIC) non polar - polar (NOT SCUBE) 9.7 KF is a strong electrolyte, and HF is a weak electrolyte. How is the solution of KF different from that of HF? CONTINUED ON NEXT PAGE →
question 9.5)

can someone please explain to me why CaCO3 is soluble in water and not carbon tetrachloride (CCl4)? thank you ?!

Answer 1

Solution:

CaCO3 is an ionic compound. It is slightly soluble in water due to small dissociation of Ca2+ and CO3^2- ions. Water being the polar solvent creates ion-dipole interaction and hence able to dissolve CaCO3 slightly. Its solubility increases with increasing concentration of CO2 in water due to formation of bicarbonates.

On the other hand, CCl4 is a non polar solvent, hence it is unable to form ion-dipole interaction with CaCO3. Therefore, it is completely insoluble in water.