Question

1a) Consider the elbow joint pictured. Given that the muscle connection distance is d=1.29 cm and the barbell mass is M=7.0 kg, find the muscle tension force? 3552 ✓N muscle tension F E distance d barbel in hand 555cm long, 3 kg rod b) What is the rotational inertia of the arm/barbell system? 2.42 kgm? c) If the arm begins at rest and accelerates through 45° in 303 millseconds, find the angular acceleration: rad/s2 Check d) What muscle tension will be required to accelerate the arm in this manner? Check

Answer 1

I = 2.42 Kogma o = 45° = I radians t = 303ms = 0.3035 we have Boltart) 0= wait t - oto wo=0 I ata a = 20 2x 1/4 C0.30313 a = 17.11 Vad/s2

we have bosque , f = IL 8 = 2.42 x 17.11 8 = 4104Nm T = Ex d = 41.44 0.0109 F = 32 10. LN (tension)