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tal Score: Save Submit Assignment for Gra Submit Assian Exercise 07.17 Algorithmic Question 4 of Check My Wor eBook Suppose a
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Answer #1

a)
If the population size is infinite, then the standard error of the mean = Standard deviation / n^(1/2)
= 11 / 42^(1/2)
= 11 / 6.4807407
= 1.70

b)
If the population size (N) = 50,000 then the standard error of the mean = (Standard deviation / n^(1/2)) * ((N - n) / (N - 1))^(1/2)
= (11 / 42^(1/2)) * ((50,000 - 42) / (50,000 - 1))^(1/2)
= 1.6973 * 0.999589908
= 1.70

c)
If the population size (N) = 5,000 then the standard error of the mean = (Standard deviation / n^(1/2)) * ((N - n) / (N - 1))^(1/2)
= (11 / 42^(1/2)) * ((5,000 - 42) / (5,000 - 1))^(1/2)
= 1.6973 * 0.995890
= 1.69

d)
If the population size (N) = 500 then the standard error of the mean = (Standard deviation / n^(1/2)) * ((N - n) / (N - 1))^(1/2)
= (11 / 42^(1/2)) * ((500 - 42) / (500 - 1))^(1/2)
= 1.6973 * 0.958037406
= 1.63


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