Question

Example. The H₂ gas collected at 30°c and Volume 641 mL and 988mm HG pressure What is the mass Cingram of the Hagas PH2 = Ptotal - PH2O 4 31.82 mm HG 0659

Answer 1

e bu = Atmospheric pressure - Vapor pressure of wales = (988 – 31.82), mm Hg. . = 956-18 mm Hg = (956.18) atm. 760 V = 641 ml = 0.641L. R = 0.0821 L-atu motak T = (30+ 273.15) K = 303•15k Now, PV=nRT = WRT. . op w - PH₂X VX M M = Molar mass of H2=2 g 1mo. RT W = mass of H2(g) : 956.18 0.641 X 2 760 ^ 0:0821x303-15 = 0.0657 .: Mass of H2 gas = 0.065g (Ans) 4 NH3(g)+ 5024)→ 4N0GQh+ 6H2008). 5 mol of O₂ reacts with 4 mol of NH3 1.19 of 02 99 g 4 99. ^ ” The volume of 4 moi Nhz at STP = 4X22:44 L IP = 1 atm ni = AX 22:41 Ti = 2 73.15K 1P2 = 5 atm mer-1358.15 x 4x22: 41. To = (85+273.15K= 35895- . 273:15 X 5 X5 Now, PINI = P2 V 2 = 5 T2 I X4 X22 273.15 x 5 5 *V2 358:15 or V2 =( . - 4.70L ... The volume of the required NH3 gas will be 4.7 1 (Ans)