Question

1 A ball is dropped from 20.0 ft above the ground. Using energy considerations only, what is the velocity (in ft/s) of the ball just as it hits the ground? Enter answer 2 What is the velocity (in m/s) of a 55.0 kg jogger with a kinetic energy of 1,380.0 J? Enter answer 3. A small sports car and a pickup truck start coasting down a 35.0 m hill together, side by side Assuming no friction, what is the velocity (in m/s) of both vehicles at the bottom of the hill? Enter answer 4. A 65.0 kg student runs up the stairs of a football stadium to a height of 15.0 m above the ground in 10.0 s. What is the power of the student in kw? Enter answer The potential energy of a 15.0 kg ball is 2,420 J while at rest. If the ball is released, how fast will it be moving in m/s when it strikes the ground? Enter answer
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Answer #1

1.

mgh=rac {1}{2}mv^2  

v=sqrt {2gh}

2.32.2.20 ft/s=3588 ft/s u=

2.

ーmu-1380 J

2 5502 = 1380 J

u = 7.084 m/s

3.

v=sqrt {2gh}

v- V2.9.8 35 m/s 26.19 m/s

4.

W mgh 65 9.8-15 W 0.955 W 10

5.

2420 mg 15-98 m = 16,46 m

v- /2gh- V2 9.8 16.46 m/s 17.96m/s

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