Answer
Ksp = 2.92 × 10-44
Explanation
Solubility equilibrium of Pb3(PO4)2 is
Pb3(PO4)2(s) <-------> 3Pb2+(aq) + 2PO43-(aq)
Ksp = [Pb2+]3[PO43-]2
at saturated solution
[Pb2+] = 3 × 7.7 ×10-10M = 2.31 × 10-9 M
[PO43-] = 2 × 7.7 ×10-10M = 1.54 ×10-9M
Ksp = ( 2.31 ×10-9)3 ( 1.54 ×10-9)2
Ksp = 2.92 × 10-44
the molor solubility for Pb3(po4)2 is 7.7 x 10^-10 moles L ^-1. calculate kap
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