Question

A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 44.751 mg of carbon dioxide and 18.319 mg of water. In another experiment, 30.199 mg of the compound is reacted with excess oxygen to produce 13.05 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements.

A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 44.751 mg of carbon dioxide and 18.319 mg of water. In another experiment, 30.199 mg of the compound is reacted with excess oxygen to produce 13.05 mg of sulfur dioxide Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements. empirical formula: C5H3SO2

Answer 1

Experiment - Moles of c = 44.751 x 108 g = 1.017 x 10 mol 4ч Mass of c = 1.017 X100 mal x lagi mol = 0.0122 g % c in the sample a 0.0122g x 100 = 48.56% 0.025121 g Maase 2.035 x 103 male moles of H= 18.319 x 100 g x2= 18glna mass of Hi = 2.035 x 10 ml x Iglmal = 0.002035g H in the sample 0.00 2035 g x 100 - 8.10% 0.025121g Experiment - Mosongrona g = 2.039 x 10 moes 13.05 X 10 Molls of s= 6ч 1 hot a = 6.525 X 10 g - 4 32g / ind Mass y s = 2.039 x 10 mal x fos in the sample = 6.525x10g x 100 = 21.6% 30.199 X 103g Moles of 0.025121g sample = 2.039 x 10 mol x 0.0251219 30.199 Xid 4 = 1.696 x 10 mol % 0 = 100 - 148.56 + 8.1 +21.6) = 21.74% Mass in sample = 0.02512 g x 21.74 = 5.46 X 10 g

Moles of o= 3.41 x 104 mal Ratio y moles of CiH:3:0 = Herodos : 1.017 x103 : 2.035 x 103 : 200 : 3.41 104 1.696 X 10 Divide by smallest number CoHis:0 = 6 8 12 : 1:2 so, the empirical formula of the compound is othed CGH12SO2