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Answer Part A-C please, thanks.

II Review | Constants | Periodic Table A 0.32 mol amount of NH3 is dissolved in 0.47 L of a 0.38 M silver nitrate solution. K

Part B Calculate the equilibrium concentration of NH3 in the solution. Express your answer to one significant figure and incl

Part C Calculate the equilibrium concentration of Ag(NH3), in the solution. Express your answer to four significant figures a

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Answer #1

Ag+ + 2Nng - Tag whg 7 2 = [ Az C NH3)2+ [Agt] [Nr. 2² 1.7x10-17 - [Ag Cruz) 27 [Ag+] [Muz?? - Moles of Agt = 0.38 x 0.47 = 0АЭ ары = [A2 сы», - - 30 - 3 . Очх .01 - 4 х . +•3 - 3 - Е - x) - 1.2 х 10- (es * ) ) » ж . 3ч x 2, 3, 4 - очҒх ге: оч - ).

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