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7. 0/2 points Previous Answers SerPSE10 9.4.P.015. My Notes A car of mass m moving at a speed V, collides and couples with the back of a truck of mass 4m moving initially in the same direction as the car at a lower speed V2. (Use any variable or symbol stated above as necessary.) (a) What is the speed Vf of the two vehicles immediately after the collision? Vf= (b) What is the change in kinetic energy of the car-truck system in the collision? AK =

Answer 1

Date Ve=2 Given, mass of car=m mass of truck=4m Speed of car-v, speed of truck= V₂ (a) For perfectly Inelastic collisien (cas-Touck coupled together to Applying conserwatien Og linear momentum mvit m₂ V2 = 1m, + m2) m VIDA (4m) 22 m+47) VF Vf= m [ v1 + 4V2] =) Ve= V1 + 4V2 57 5 (6) Initial Kinetic energy - 1 mV,2 + 2 (4m) , ? - = 4(?441,2) (otum) mlf V, + 402) Final kinetic energy a 81 b. AKE = kg-ki1m (7,+402)2-(Ví + 402)] - 4m|K?+6v++8VIV- W2 - 4139 AKE = m(GV2² + 4V1 V2 LAKE = m[662² + 4vi02] 10/11