16) balanced chemical reaction
2C2H4 + O2 -----> 2C2H4O
Molar mass of ethane = 28.0 g
Molar mass of ethylene oxide = 44.0 g
A) 56.0 g ethane produced---> 88.0 g ethylene oxide
120 g ethane produced---> 88×120/56 => 188.6 g
So Theoretical yield = 188.6 g
B) % yield = Actual mass×100/Theoretical mass
=> 180×100/188.6
=> 95.5%
16. The gas ethane, C2H4, reacts with oxygen gas to form ethylene oxide, C2H40, according to...
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