(5)
NPV of geometric gradient series = 1000/1.05 + 700/1.052 + 490/1.053 + 343/1.044 = $2303.78
Let the linear gradient series start with x and reduce by a
Hence, CF0 = a
CF1 = a-x
CF2 = a-2x
CF3 = a-3x
Hence, NPV of linear series = a + (a-x)/1.05 + (a-2x)/1.052 + (a-3x)/1.053 = 3.72a - 5.36x
This is equal to NPV calculated earlier
=> 3.72a - 5.36x = 2303.78
Also, CF4 = 0 => a-4x = 0 => a = 4x.. putting this is equation above,
3.72*4x - 5.36x = 2303.78 => x = 242
=> a = 968
Hence,
CF0 = $968
CF1 = 968 - 242 = $726
CF2 = 968 - 2*242 = $484
CF3 = 968 - 3*242 = $242
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