Question

Question 3 1 pts A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity 4.184 J/g K) at initial temperature 80.000 C. A salt weighing 6.303 g is quickly added. The salt has a molar mass of 321.692 g/mol. The final temperature of the solution is 43.252 C. Assume no heat loss to the surroundings. Assume the specific heat capacity of the solution is equal to that of pure water, and that the mass of the solution is equal to the mass of the solid plus the mass of water in the calorimeter. What is the molar heat of solution for the salt, in kJ/mol? Report your answer to three digits after the decimal.

Answer 1

784.708 KJ/mol

Or more accurate is 784.726 KJ/mol

Use formula amount of heat the calculate to water ost/ained y where, heat lost/aained in J in m = mars grams Specific heat capacity in AT change in Tempinatune in K. 100 000 mas af waten c of wateN initial temprature. 4 14 Tk (273-15 80) 35 2-15 K (273-15 43-25 2k - 316.40 2 finat tempnatune mc AT 1009 X 4.1 4L x316.402-253-15k x (-36.74) k X 4 184 J 15.375 J heat is ielease d by water Nejative sign indicate that

15.375 J huat is ost y water and thy theat obsorhad ey chomical eation 15 375 J 6.303 absorb heat heat salt 15335 J 6303 salt absanta 15 375 x 321692 6 303 J absarb hiat salt 321 92 F4726 J 384-108 KJ 1 male salt(321 692 is absorbed by Heat 384 308 KJ. = 84.708 KJ mol ie Malan heatof salution for salt