Question

8 Question (1 point) 1st attempt The reaction of 5.60 g of carbon with excess O2 yields 14.6 g of CO2. What is the percent yield of this reaction?

Answer 1

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I know, atomic mass of Carbon = 12 atomic mass d o = 16 Yield of co2 = 14.69 Molar mass of co₂ = Mcarten + 2.X Mosogen = 12 + (2016) = 44 Number of Moles in 5.6.gm of carbon = 5.6 - 0.467 12 The balanced_chemical equation for reaction is - Cut O216 (Only) According to Stoichiometry One mole of C gives one mole of CO2 so 0.467 moles of C gives 0.467 moles of CO2 Mass-04-0.46 moles.of CO2 = 0.467x Mcom - 0.467 x 44 = 20.53_ Percentage yield = Actual yield loo Theoret x 100 = 14.6 20.53 71.11%

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