For reference, I did this exact question before on the homework and got it right, but I don't remember one step in how I got the answer (which was 0.769). I do have some notes of that problem right here:
Restaurant A | Restaurant B | Restaurant C | Restaurant D | |
Order Accurate | 310 | 268 | 238 | 135 |
Order Not Accurate | 37 | 50 | 34 | 12 |
951 |
1084 |
(I don't know what to do with the numbers above to get to the answer below):
0.769 |
And here is the new (but also the same) problem I now need solved:
As always, thank you for your time!
Restaurant A | Restaurant B | Restaurant C | Restaurant D | Total | |
Order Accurate | 310 | 268 | 238 | 135 | 951 |
Order Not Accurate | 37 | 50 | 34 | 12 | 133 |
Total | 347 | 318 | 272 | 147 | 1084 |
Out of 1084 orders 951 orders are accurate. | |||||
If 2 orders are selected, the probability that both are accurate is =(951/1084)*(950/1083) = 0.769 |
For reference, I did this exact question before on the homework and got it right, but...
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