Question

and with minitab please.

2. In a metallurgy lab, there are two different analytical tests that can be used to determine the impurity level in steel alloys. The engineer believe that Test 1 will capture more impurities in the specimen than Test 2. Eight specimens are tested using both procedures, and the results are shown in the following tabulation. Using 5% significance, investigate if the engineer's assumption if correct. Specimen Test 1 Test 2 1.7 2.0 1.6

Answer 1

WINTERHONENLAND TWO-Sample T-Test and Cl: Test1, Test2 Two-sample I for Testl vs Test2 N Testl 8 Test2 8 Mean StDev SE Mean 1.513 0.181 0.064 1.662 0.325 0.11 Difference = mu (Testl) - mu (Test2) Estimate for difference: -0.150 95% lower bound for difference: -0.388 T-Test of difference = 0 (vs >): I-Value = -1.14 P-Value = 0.860 DF = 10 MTB >

Ans. Hypothesis Ho: eli - U2 vs. - HI : 41 42 ni = n2-8. x=0:05 Here Pralue =0.860> 0.05 Accept Ho. Conclusion: Hence we conclude that the testl and test 2 measures the same impwcity level in steal alloys.